Kylian Mbappé nominated for The Best - FIFA Player of the Year 2019
Paris Saint-Germain forward Kylian Mbappé is one of the ten players nominated for the prestigious trophy: The Best - FIFA Player of the Year 2019.
The winner will be voted for by national team coaches and captains, selected journalists and internet users on FIFA.COM. The votes of all four groups will be weighted (25% each one) to determine the outcome. You can vote until midnight on 19 August.
The Best - FIFA Player of the Year 2019 nominees:
Frenkie de Jong (Netherlands - Ajax/NED then Barcelona/ESP)
Matthijs de Ligt (Netherlands - Ajax/NED then Juventus/ITA)
Eden Hazard (Belgium - Chelsea/ENG then Real Madrid/ESP)
Harry Kane (England - Tottenham/ENG)
Sadio Mané (Senegal - Liverpool/ENG)
Kylian Mbappé (France - Paris Saint-Germain/FRA)
Lionel Messi (Argentina - Barcelona/ESP)
Cristiano Ronaldo (Portugal - Juventus/ITA)
Mohamed Salah (Egypt - Liverpool/ENG)
Virgil van Dijk (Netherlands - Liverpool/ENG)
#TheBest
— FIFA.com en français ⚽ (@fifacom_fr) July 31, 2019
🇵🇹 Cristiano Ronaldo
🇳🇱 Frenkie de Jong
🇳🇱 Matthijs de Ligt
🇧🇪 Eden Hazard
🏴 Harry Kane
🇸🇳 Sadio Mane
🇫🇷 Kylian Mbappe
🇦🇷 Lionel Messi
🇪🇬 Mohamed Salah
🇳🇱 Virgil van Dijk
Alors ? À qui le trophée du meilleur joueur du Monde selon vous ? pic.twitter.com/CJi3oxywWP